Shakur Stevenson Promises Knockout Against O’Shaquie Foster: 'I Don’t Run From Nobody'
In a heated exchange post-fight, Shakur Stevenson declared his intent to knock out WBC champion O’Shaquie Foster, intensifying their rivalry.
Shakur Stevenson, the WBO super-lightweight champion, has vowed to deliver a knockout against O’Shaquie Foster following a fiery confrontation in the ring. Stevenson, who captured his title with a unanimous decision over Teofimo Lopez in January, is currently weighing his options between remaining at 140lbs or moving back down to lightweight.
After Foster retained his WBC super featherweight belt with a majority decision win over Ray Ford, the two fighters engaged in a heated face-off. Stevenson took to social media to express his frustration, stating, "Look they starting already, This dude scream my name on every platform... I never run from nobody, I’m a man first gang. Let’s get it." His comments reflect a growing animosity as he seeks to avenge Ford's loss.
Foster has indicated a willingness to move up to 140lbs for a potential showdown, but he also suggested that a fight at 135lbs would be more equitable for Stevenson. As the rivalry heats up, fans are eager to see if these two champions will finally meet in the ring.
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